++         Cell c0 = 2
> +++++    Cell c1 = 5

[          Start loop with the cell pointer on the loop counter (c1)
  < +        Add 1 to c0
  > -        Subtract 1 from c1
]          End loop with the cell pointer on the loop counter

           At this point our program has added 5 to 2 leaving 7 in c0
           and 0 in c1 BUT we cannot output this value to the terminal
           since it's not ASCII encoded

           To display the ASCII character "7" we must add 48 to the
           value 7!  48 = 6 * 8 so let's use another loop to help us

++++ ++++  c1 = 8 and this will be our loop counter again
[
< +++ +++  Add 6 to c0
> -        Subtract 1 from c1
]
< .        Print out c0 which has the value 55 which translates to "7"