Making a much shorter Zoidac calculator using lists

Remember our Chinese restaurant problem from earlier in the semester?

• Year	Zodiac Sign
  2012	Dragon
  2013	Snake
  2014	Horse
  2015	Sheep
  2016	Monkey
  2017	Rooster
  2018	Dog
  2019	Pig
  2020	Rat
  2021	Ox
  2022	Tiger
  2023	Rabbit

At that time we could only solve this using a long list of conditionals.

But there is a MUCH easier way.

Write a Python function that conforms to the following BUT, does this without using any conditionals at all. Instead, define a list containing the 12 different animals in the list. If you put the animals in the list in the right order you can use the index of the list and the modulo math of the year to work together to be a "simple" lookup.

• Function name
  • zodiac()
• Inputs
  • asks for the year
• Returns
  • one of 12 Strings based on the table above
• Example(s)