outcome: Apple Banana Cake Doughnut Eclair P(outcome) .3 .1 .4 .1 .1
and a random variable X the function:
outcome Apple Banana Cake Doughnut Eclair X(outcome) 1 1 10 5 12
the resultant probability distribution function of X is
X 1 5 10 12 P(X) .4 .1 .4 .1
Often we shall be working with probability distributions without knowing the
probability space or random variable which produced them.
Analogous to when we had a frequency distribution, for
a probability
distribution we can calculate the mean of a random variable X which
is called the expected value
and denoted by
E[X] = *sum*x(i)P(x(i))= *sum* x(i)p(i)
We can also calculate the variance which is denoted by
V[X] = *Sum* ((x(i)-E[X])^2) p(i)
In the above example, the mean is E[X] = 1 × .4 + 5 × .1 + 10
× .4 +
12 × .1 = 6.1
and the variance is: V[X] = *Sum* ((x(i)-E[X])^2) p(i) =
(1-6.1)^2 × .4 + (5-6.1)^2 × .1 + (10-6.1)^2 × .4 +
(12-6.1)^2 × .1 = 20.0860
As before, the standard deviation (denoted by a lower case sigma) is the
square root of the variance, in this example 4.4817.
Two rules for means and variances of random variables which shall be useful are:
Competencies: Calculate the expected value, variance, and standard deviation for the following probability distribution function:
X 1 3 9 12 P(X) .3 .2 .4 .1Reflection: How can a given experiment be associated with different probability distribution functions? How can different experiments be associated with the same probability distribution function?